請(qǐng)問(wèn)我這個(gè)程序有什么錯(cuò)誤嗎？
int num =999; int count = 0; for(;num>0;) { ? ?num=num/10; ? ?count+=1; ? ?if(count>10) ? ?{ ? ? break; ? ?} } System.out.println("它是個(gè)"+count+"位數(shù)");
ideally
2017-04-08
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2017-04-09
樓主可以這樣寫(xiě),你可以看看:
import java.util.Scanner;
public class HelloWorld {
????public static void main(String[] args) {
????????Scanner sca = new Scanner(System.in);
????????System.out.println("請(qǐng)輸入一個(gè)整數(shù): ");
????????int num = sca.nextInt();
????????int count = 0;
????????while (num > 0) {
????????????num = num / 10;
????????????count += 1;
????????}
????????System.out.println("您輸入了一個(gè) ?" + count + " ?位數(shù)");
????????if (count > 10) {
????????????System.out.println("輸入錯(cuò)誤");
????????}
???}
}
2017-04-09
表示樓主代碼沒(méi)啥問(wèn)題
2017-04-08
我也不知道，就是直接寫(xiě)的，eclipse運(yùn)行正常，請(qǐng)大佬們參考參考，提提意見(jiàn)
public?class?HelloWorld? { ????public?static?void?main(String[]?args) ????{ ???? int?num?=999;?? ???? int?count?=?0; ???? for(;num>0;) ???? ???{ ???? ??num=num/10;???? ???? ??count+=1; ???? ???} ???????System.out.println("輸入的數(shù)是"?+?count?+?"位數(shù)"); ???? ???? ???if?(count>10)? ???? ???????{ ???? ????System.out.println("輸入錯(cuò)誤"); ???? ???????} ???? ????} }2017-04-08
問(wèn)一下錯(cuò)誤的提示是什么??？