<?php
class Car {
??? public $name = 'car';
?? ?
??? public function __clone() {
??????? $obj = new Car();
??????? //$obj->name = $this->name;

??????? $obj->name='test';

??? }
}
$a = new Car();
$a->name = 'new car';
$b = clone $a;
echo $b->name;

?>

我的問題是$b = clone $a;此時$b是指由$a調(diào)用__clone生成的對象還是？如果是那么echo $b->name;應(yīng)該打印的值是‘test’,而實際結(jié)果確是 new car