>>>?listMax=[]
>>>?i=0
>>>?j=0
>>>?
>>>?while?i<10:
...?????while?j<10:
...?????????d=abs(list_initial[i]-list_initial[j]).max()
...?????????listMax.append(d)
...?????????j=j+1
...?????i=i+1
...?
>>>?
>>>?listMax
[0.0,?1.653936494127882,?0.71496036431101384,?0.55047599121246971,?0.97650531286894926,?0.22584233947870302,?0.39368112947658396,?0.78142550568467184,?0.22282862934663961,?0.13049151805132664]數(shù)據(jù)是一個(gè)10＊107的矩陣
2 回答
___C___
TA貢獻(xiàn)168條經(jīng)驗(yàn) 獲得超109個(gè)贊
因?yàn)榈谝淮窝h(huán)后，j的值就永遠(yuǎn)是10了。所以， 在第一次循環(huán)你要初始化一下j=0;
while?i<10:
...? ? ?j = 0;
...?????while?j<10:
...?????????d=abs(list_initial[i]-list_initial[j]).max()
...?????????listMax.append(d)
...?????????j=j+1
...?????i=i+1
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