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spring mvc 有如下兩個(gè)映射，應(yīng)該怎么處理這兩個(gè)映射呢？

Spring

滄海一幻覺(jué) 2023-04-04 21:17:09

@RequestMapping(value="/users/{id}") public String renderUser(@PathVariable("id") int id){ //do something}@RequestMapping(value="/users/{id}.{format}") public String renderUserOf(@PathVariable("id") int id,@PathVariable("format") String format){ //do something}第一個(gè) "/users/{id}" 能夠正常處理但是第二個(gè) /users/{id}.{format} 卻不能正常解析比如 /users/7 會(huì)被映射為 "/users/{id}" ,但 /users/7.json 卻也被映射為了 "/users/{id}"

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1 回答

繁星coding

TA貢獻(xiàn)1797條經(jīng)驗(yàn) 獲得超4個(gè)贊

Spring根據(jù)后綴來(lái)決定編組格式.
如果你想返回json.

<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
                <!-- 設(shè)置為false開(kāi)啟對(duì)Accept Header的支持-->
                <property name="ignoreAcceptHeader" value="false"/>
                <!-- 在沒(méi)有擴(kuò)展名時(shí)的默認(rèn)形式 -->
                 <property name="defaultContentType" value="application/xml"/>        
       
        <property name="mediaTypes">
            <map>
                <entry key="json" value="application/json" />
                <entry key="xml" value="application/xml" />
                <entry key="jsp" value="text/html"/>
                <entry key="do" value="text/html"/>
            </map>
        </property>
        <property name="viewResolvers">
            <list>          
                <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
                    <property name="viewClass" value="org.springframework.web.servlet.view.InternalResourceView"/>
                    <property name="prefix" value="/WEB-INF/jsp/"></property>              
                </bean>
                <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" />
             
            </list>
        </property>
        <property name="defaultViews">
            <list>            
                <!-- for application/xml -->           
                <bean class="org.springframework.web.servlet.view.xml.MarshallingView" >
                    <property name="marshaller">
                        <ref bean="castorMarshaller"/>
                    </property>
                </bean> 
                <!-- for application/json -->  
                <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />                
            </list>
        </property>
    </bean>

請(qǐng)求id.xml就得到xml格式的,請(qǐng)求id.json就是json格式的~沒(méi)有后綴名會(huì)根據(jù)Accept類(lèi)型.

反對(duì) 回復(fù) 2023-04-07