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為什么提示vb 實時錯誤‘91’對象變量或 With 塊變量沒有設(shè)置?

為什么提示vb 實時錯誤‘91’對象變量或 With 塊變量沒有設(shè)置?

忽然笑 2023-04-20 19:15:10
Public Function viewData(ByVal txtSQL As String, dataGridAll As DataGrid) As IntegerDim rstData As ADODB.RecordsetDim result As String'檢索需要的信息result = ExecuteSQL(txtSQL, rstData, False)'設(shè)置datagrid的數(shù)據(jù)源If rstData.RecordCount <> 0 ThenSet dataGridAll.DataSource = rstDataviewData = rstData.RecordCountElseMsgBox "還沒有數(shù)據(jù)!", vbOKOnly + vbExclamation, "警告"viewData = 0End IfEnd Function數(shù)據(jù)庫采用sql2000'函數(shù)名:ExecuteSQL'說 明:執(zhí)行SQL語句'參 數(shù):SQL As String, rst As ADODB.Recordset, Optional enableWrite As Boolean'返回值:SQL語句執(zhí)行成功——true,失敗——false' ******************************************************************************Public Function ExecuteSQL(ByVal SQL As String, rst As ADODB.Recordset, _Optional enableWrite As Boolean = True) As BooleanDim con As New ADODB.ConnectionDim sTokens() As StringOn Error GoTo Execute_ErrorsTokens = Split(SQL)Set con = New ADODB.Connectioncon.Open ConnectStringSet rst = New ADODB.RecordsetIf enableWrite Thenrst.Open Trim$(SQL), con, adOpenStatic, adLockOptimisticElserst.Open Trim$(SQL), con, adOpenStatic, adLockReadOnlyEnd IfExecuteSQL = TrueExit FunctionExecute_Error:ExecuteSQL = FalseExit FunctionEnd Function
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1 回答

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四季花海

TA貢獻(xiàn)1811條經(jīng)驗 獲得超5個贊

ExecuteSQL 這個函數(shù)貼出來,估計是數(shù)據(jù)庫沒鏈接上

Public Function viewData(ByVal txtSQL As String, dataGridAll As DataGrid) As Integer 
Dim rstData As ADODB.Recordset 
Dim result As String 
'檢索需要的信息 
result = ExecuteSQL(txtSQL, rstData, False) 
if result=true then
'設(shè)置datagrid的數(shù)據(jù)源 
If rstData.RecordCount <> 0 Then 
Set dataGridAll.DataSource = rstData 
viewData = rstData.RecordCount 
Else 
MsgBox "還沒有數(shù)據(jù)!", vbOKOnly + vbExclamation, "警告" 
viewData = 0 
End If 
else
msgbox "數(shù)據(jù)庫鏈接失敗"
end if
End Function

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反對 回復(fù) 2023-04-23
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