(1+2)：計算結(jié)果為 3（整數(shù)，不是元組）
((1+2),)：是一個嵌套元組（內(nèi)部元素是 3），屬于元組
('a'+'b')：計算結(jié)果為 'ab'（字符串，不是元組）
(1, )：是包含一個整數(shù)的元組，屬于元組
(1,2,3,4,5)：是包含 5 個整數(shù)的元組，屬于元組
因此，共 3 個
((1+2),)：是一個嵌套元組（內(nèi)部元素是 3），屬于元組
('a'+'b')：計算結(jié)果為 'ab'（字符串，不是元組）
(1, )：是包含一個整數(shù)的元組，屬于元組
(1,2,3,4,5)：是包含 5 個整數(shù)的元組，屬于元組
因此，共 3 個
2025-09-24
第一次刪除 'Candy'（索引 2）后，列表元素的索引會自動重新排列
原來的 'David' 的索引從 3 變?yōu)?2，因此第二次需要刪除索引 2 才能正確移除 'David'
最終結(jié)果為 ['Alice', 'Bob', 'Ellena']，符合預(yù)期
原來的 'David' 的索引從 3 變?yōu)?2，因此第二次需要刪除索引 2 才能正確移除 'David'
最終結(jié)果為 ['Alice', 'Bob', 'Ellena']，符合預(yù)期
2025-09-24
第一個里，a是 'python'（有用），所以用它，輸出hello, python
第二個里，b是空的（沒用），所以用后面的 'world'，輸出hello, world
第二個里，b是空的（沒用），所以用后面的 'world'，輸出hello, world
2025-09-24
num0=[]
num1=[]
flag=False
for itemL in L:
for itemS in S:
if itemL==itemS:
num0.append(itemS)
flag=True
break
if flag==False:
num1.append(itemL)
if flag==True:
flag=False
num1=[]
flag=False
for itemL in L:
for itemS in S:
if itemL==itemS:
num0.append(itemS)
flag=True
break
if flag==False:
num1.append(itemL)
if flag==True:
flag=False
2025-08-17
# -*- coding: utf-8 -*-
調(diào)用函數(shù)出現(xiàn)中文需備注上訴內(nèi)容。
調(diào)用函數(shù)出現(xiàn)中文需備注上訴內(nèi)容。
2025-08-12
def func(**kwargs):
n = kwargs['names']
g = kwargs['gender']
a = kwargs['age']
index = 0
for name,gender,age in zip(n, g, a):
print('name: {},gender: {},age: {}'.format(name,gender,age))
func(name = ['吳宣儀','趙露思','高亞星'], gender = ['girl', 'girl', 'girl'], age = [25,28,27])
n = kwargs['names']
g = kwargs['gender']
a = kwargs['age']
index = 0
for name,gender,age in zip(n, g, a):
print('name: {},gender: {},age: {}'.format(name,gender,age))
func(name = ['吳宣儀','趙露思','高亞星'], gender = ['girl', 'girl', 'girl'], age = [25,28,27])
2025-08-12
def greet(param='world'):
print('Hello,{}.'.format(param))
greet()
greet(123)
print('Hello,{}.'.format(param))
greet()
greet(123)
2025-08-12
def func(p):
sum_c = 0
mul = 1
if isinstance(p,list):
for i in param:
sum_c += i
return sum_c
if isinstance(p,tuple):
for i in range(len(p)):
mul *= p[i]
return mul
c = func((1,2,15))
print(c)
p = func([1,12,3])
print(p)
sum_c = 0
mul = 1
if isinstance(p,list):
for i in param:
sum_c += i
return sum_c
if isinstance(p,tuple):
for i in range(len(p)):
mul *= p[i]
return mul
c = func((1,2,15))
print(c)
p = func([1,12,3])
print(p)
2025-08-12
def sum_num(n):
if n == 1:
return 1
return n + sum_num(n-1)
sum_number = sum_num(100)
print(sum_number)
if n == 1:
return 1
return n + sum_num(n-1)
sum_number = sum_num(100)
print(sum_number)
2025-08-12
def sub_sum(list):
sum_even = 0
sum_odd = 0
for i in range(len(list)):
if i % 2 == 0:
sum_even += list[i]
else:
sum_odd += list[i]
return sum_even,sum_odd
s_even,s_odd = sub_sum([1,2,5,9,3,11])
print("s_even: ",s_even)
print("s_odd: ",s_odd)
sum_even = 0
sum_odd = 0
for i in range(len(list)):
if i % 2 == 0:
sum_even += list[i]
else:
sum_odd += list[i]
return sum_even,sum_odd
s_even,s_odd = sub_sum([1,2,5,9,3,11])
print("s_even: ",s_even)
print("s_odd: ",s_odd)
2025-08-12
def square_of_sum(list):
sum = 0
for i in list:
sum += i * i
return sum
sum_num = square_of_sum([1,2,3])
print(sum_num)
sum = 0
for i in list:
sum += i * i
return sum
sum_num = square_of_sum([1,2,3])
print(sum_num)
2025-08-12
def sum(list):
sum = 0
for i in list:
sum += i * i
return sum
list_num = []
for i in range(1,100):
list_num.append(i)
sum_num = sum(list_num)
print(sum_num)
sum = 0
for i in list:
sum += i * i
return sum
list_num = []
for i in range(1,100):
list_num.append(i)
sum_num = sum(list_num)
print(sum_num)
2025-08-12